Advertisements
Advertisements
Question
Take `(-3)/2"p"+"q"-"r"` from `1/2"p"-1/3"q"-3/2"r".`
Solution
`(1/2"p"-1/3"q"-3/2"r")-(-3/2"p"+"q"-"r")`
= `1/2"p"-1/3"q"-3/2"r"+3/2"p"-"q"+"r"`
= `1/2"p"+3/2"p"-1/3"q"-"q"-3/2"r"+"r"`
= `(3"p"+9"p"-2"q"-6"q"-9"r"+6"r")/6` ..........[Since L.C.M. = 6]
= `(12"p")/6-(8"q")/6-(3"r")/6`
= `2"p"-4/3"q"-1/2"r"`
APPEARS IN
RELATED QUESTIONS
Find the sum of a2 − ab + bc, 2ab + bc − 2a2 and − 3bc + 3a2 + ab.
Add the following expression:
a3 − 2b3 + a, b3 − 2a3 + b and − 2b + 2b3 − 5a + 4a3
Subtract:
5a − 3b + 2c from a − 4b − 2c.
Subtract:
4x − 6y + 3z from 12x + 7y − 21z.
Take − ab + bc − ca from bc − ca + ab.
The sum of two expressions is 3a2 + 2ab – b2. If one of them is 2a2 + 3b2, find the other.
Fill in the blanks:
4 × 7 = .............. and 4ax × 7x = ............
Fill in the blanks:
1 × 8 = .............. and a2xy2 × 8a3x2y = ............
Fill in the blank:
6 × 6x2 × 6x2y2 = ...................
Fill in the blank:
− 8x × − 3x = − ....................