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The Age of the Father is Seven Times the Age of the Son. Ten Years Later, the Age of the Father Will Be Thrice the Age of the Son. Find Their Present Ages. - Mathematics

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प्रश्न

The age of the father is seven times the age of the son. Ten years later, the age of the father will be thrice the age of the son. Find their present ages.

योग

उत्तर

Let the present age of father = x years and that of son = y years
After 10 years,
father's age = (x + 10) years
son's age = (y + 10) years
According to given information, we have
x = 7y   ....(i)
And,
(x + 10) = 3(y + 10)
⇒ x + 10 = 3y + 30
⇒ x - 3y = 20
⇒ 7y - 3y = 20        ...[From (i)]
⇒ 4y = 20
⇒ y = 5
⇒ x = 7 x 5
= 35
Thus, the present age of son is 5 years and that of father is 35 years.

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Methods of Solving Simultaneous Linear Equations by Elimination Method
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अध्याय 8: Simultaneous Linear Equations - Exercise 8.3

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फ्रैंक Mathematics [English] Class 9 ICSE
अध्याय 8 Simultaneous Linear Equations
Exercise 8.3 | Q 12

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