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Solve the Following Pairs of Linear (Simultaneous) Equation Using Method of Elimination by Substitution:X/6 + Y/15 = 4 X/3 - Y/12 = 4 3/4 - Mathematics

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प्रश्न

Solve the following pairs of linear (simultaneous) equation using method of elimination by substitution:
`x/6 + y/15 = 4`

`x/3 - y/12 = 4 3/4` 

योग

उत्तर

`x/6 + y/15 = 4`     

⇒ `[ 5x + 2y ]/30 = 4`

⇒ 5x + 2y = 120
⇒ 5x = 120 - 2y

⇒ x = `[ 120 - 2y ]/5`                   ....(1)

And,
`x/3 - y/12 = 4 3/4`

⇒ `1/3( x - y/4 ) = 19/4`

⇒ `1/3([120 - 2y]/5 - y/4 ) = 19/4`

⇒ `[ 480 - 8y - 5y ]/20 = 57/4` 

⇒ `[ 480 - 13y ]/20 = 57/4`

⇒ 480 - 13y = 285
⇒ 13y = 195
⇒ y = 15
Substituting the value of y in (1), we have

`x = [ 120 - 2 xx 15]/5 = [120 - 30]/5 = 90/5 = 18`
∴ Solution is x = 18 and y = 15

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Methods of Solving Simultaneous Linear Equations by Elimination Method
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 6: Simultaneous (Linear) Equations (Including Problems) - Exercise 6 (A) [पृष्ठ ७९]

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सेलिना Concise Mathematics [English] Class 9 ICSE
अध्याय 6 Simultaneous (Linear) Equations (Including Problems)
Exercise 6 (A) | Q 14 | पृष्ठ ७९

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