Question

The alternating current is given by

i = `{sqrt42sin((2pi)/"T""t")+10}"A"`

The r.m.s. value of this current is ______ A.

विकल्प

• 11

• 22

• 33

• 44

Answer 1

The alternating current is given by

i = `{sqrt42sin((2pi)/"T""t")+10}"A"`

The r.m.s. value of this current is 11 A.

Explanation:

`"i"_"rms" = sqrt("i"_(1"rms")^2+"i"_(2"rms")^2)`

= `sqrt((sqrt42/sqrt2)^2+10^2)`

= `sqrt121` 

⇒ `"i"_"rms"` = 11 A