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प्रश्न
The alternating current is given by
i = `{sqrt42sin((2pi)/"T""t")+10}"A"`
The r.m.s. value of this current is ______ A.
पर्याय
11
22
33
44
MCQ
रिकाम्या जागा भरा
उत्तर
The alternating current is given by
i = `{sqrt42sin((2pi)/"T""t")+10}"A"`
The r.m.s. value of this current is 11 A.
Explanation:
`"i"_"rms" = sqrt("i"_(1"rms")^2+"i"_(2"rms")^2)`
= `sqrt((sqrt42/sqrt2)^2+10^2)`
= `sqrt121`
⇒ `"i"_"rms"` = 11 A
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