Advertisements
Advertisements
प्रश्न
The area of the parallelogram ABCD is 1470 sq.cm. If AB = 49 cm and AD = 35 cm then, find the height, DF and BE
उत्तर
Area of the parallelogram = 1470 sq.cm
Considering AB = base = 49 cm
Height = DF
Area = base × height
49 × DF = 1470
DF = `1470/49`
DF = 30 cm
Now considering AD as base
Base = AD = 35 cm, height = BE
Base × Height = 1470
35 × BE = 1470, BE = `1470/35`
BE = 42 cm, DF = 30 cm, BE = 42 cm
APPEARS IN
संबंधित प्रश्न
A parallelogram has sides of 15 cm and 12 cm; if the distance between the 15 cm sides is 6 cm; find the distance between 12 cm sides.
A parallelogram has sides of 20 cm and 30 cm. If the distance between its shorter sides is 15 cm; find the distance between the longer sides.
Find the missing values.
| Base | Height | Area |
| 18 cm | 5 cm |
Find the missing values.
| Base | Height | Area |
| 8 cm | 56 sq.m |
In a parallelogram the base is three times its height. If the height is 8 cm then the area is
The height of the parallelogram is one-fourth of its base. If the area of the parallelogram is 676 sq.cm, find the height and the base
Find the area of the parallelogram ABCD if AC is 24 cm and BE = DF = 8 cm
Find the height of the parallelogram whose base is four times the height and whose area is 576 sq.cm
To find area, any side of a parallelogram can be chosen as ______ of the parallelogram.
Altitudes MN and MO of parallelogram MGHK are 8 cm and 4 cm long respectively in the below figure. One side GH is 6 cm long. Find the perimeter of MGHK.
