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प्रश्न
The base angle of an isosceles triangle is 15° more than its vertical angle. Find its each angle.
उत्तर
Let the vertical angle of the isosceles triangle = x°
∴ Each base angle = x + 15°
∴ x + 15° + x + 15° + x° = 180° ...(Sum of angles of a triangle)
⇒ 3x + 30°= 180°
⇒ 3x = 180° − 30° = 150°
∴ x =`(150°)/3=50°`
Hence vertical angle = 50°
and each base angle = 50° + 15° = 65°
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