Question

The coefficient of static friction between a wooden block of mass 0.5 kg and a vertical rough wall is 0.2. The magnitude of horizontal force that should be applied on the block to keep it adhered to the wall will be ______ N. [g = 10 ms^-2]

विकल्प

• 25

• 26

• 24

• 22

Answer 1

The coefficient of static friction between a wooden block of mass 0.5 kg and a vertical rough wall is 0.2. The magnitude of horizontal force that should be applied on the block to keep it adhered to the wall will be 25 N. [g = 10 ms^-2]

Explanation:

Applying force balance equation in vertical and horizontal direction.

Force balance in vertical direction

f_s = mg     ... (i)

F = N     ... (ii)

From equation (i) and (ii)

f_s = µN =mg

N = `"mg"/"µ"`

= `(0.5xx10)/0.2`

F = N = 25N

Hence, the magnitude of horizontal force be 25 N.