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The coefficient of static friction between a wooden block of mass 0.5 kg and a vertical rough wall is 0.2. The magnitude of horizontal force that should be applied on the block to keep it -

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Question

The coefficient of static friction between a wooden block of mass 0.5 kg and a vertical rough wall is 0.2. The magnitude of horizontal force that should be applied on the block to keep it adhered to the wall will be ______ N. [g = 10 ms-2]

Options

  • 25

  • 26

  • 24

  • 22

MCQ
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Solution

The coefficient of static friction between a wooden block of mass 0.5 kg and a vertical rough wall is 0.2. The magnitude of horizontal force that should be applied on the block to keep it adhered to the wall will be 25 N. [g = 10 ms-2]

Explanation:

Applying force balance equation in vertical and horizontal direction.

Force balance in vertical direction

fs = mg     ... (i)

F = N     ... (ii)

From equation (i) and (ii)

fs = µN =mg

N = `"mg"/"µ"`

= `(0.5xx10)/0.2`

F = N = 25N

Hence, the magnitude of horizontal force be 25 N.

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