Advertisements
Advertisements
प्रश्न
The contents of 100 match box were checked to determine the number of match sticks they contained.
Number of match sticks | Number of boxes |
35 | 6 |
36 | 10 |
37 | 18 |
38 | 25 |
39 | 21 |
40 | 12 |
41 | 8 |
(i) Calculate correct to one decimal place, the mean number of match sticks per box.
(ii) Determine how many matchsticks would have to be added. To the total contents of the 100 boxes to bring the mean up exactly 39 match sticks.
उत्तर
Number of match sticks `(x_i)` |
Number of boxes `(f_i)` |
`f_ix_i` |
35 | 6 | 210 |
36 | 10 | 360 |
37 | 18 | 666 |
38 | 25 | 950 |
39 | 21 | 819 |
40 | 12 | 480 |
41 | 8 | 328 |
`sumf_i` = 100 | `sumf_ix_i` = 3813 |
∴ Mean = `(sumf_ix_i)/(sumf_i) = (3813)/(100)`
= 38·13 ∼ 38·1.
(ii) Now the number of extra sticks to be added.
= 39 x 100 - 38·13 x 100
= 3900 - 3813 = 87.
APPEARS IN
संबंधित प्रश्न
Thirty women were examined in a hospital by a doctor and the number of heartbeats per minute were recorded and summarized as follows. Fine the mean heartbeats per minute for these women, choosing a suitable method.
Number of heartbeats per minute | 65 - 68 | 68 - 71 | 71 - 74 | 74 - 77 | 77 - 80 | 80 - 83 | 83 - 86 |
Number of women | 2 | 4 | 3 | 8 | 7 | 4 | 2 |
Find the mean of the following data:-
x | 19 | 21 | 23 | 25 | 27 | 29 | 31 |
f | 13 | 15 | 16 | 18 | 16 | 15 | 13 |
If the mean of the following data is 20.6. Find the value of p.
x | 10 | 15 | P | 25 | 35 |
f | 3 | 10 | 25 | 7 | 5 |
Find the missing frequency (p) for the following distribution whose mean is 7.68.
x | 3 | 5 | 7 | 9 | 11 | 13 |
f | 6 | 8 | 15 | P | 8 | 4 |
Find the mean of each of the following frequency distributions
Class interval | 0 - 10 | 10 - 20 | 20 - 30 | 30 - 40 | 40 - 50 |
Frequency | 9 | 12 | 15 | 10 | 14 |
Find the mean of each of the following frequency distributions
Class interval | 0 - 8 | 8 - 16 | 16 - 24 | 24 - 32 | 32 - 40 |
Frequency | 5 | 6 | 4 | 3 | 2 |
Consider the following distribution of daily wages of 50 workers of a factory:
Daily wages (in ₹) |
500-520 | 520-540 | 540-560 | 560-580 | 580-600 |
Number of workers | 12 | 14 | 8 | 6 | 10 |
Find the mean daily wages of the workers of the factory by using an appropriate method.
The mean of first n odd natural number is
The following frequency distribution table shows the amount of aid given to 50 flood affected families. Find the mean of the amount of aid.
Amount of aid
(Thousand rupees)
|
50 - 60 | 60 - 70 | 70 - 80 | 80 - 90 | 90 - 100 |
No. of families | 7 | 13 | 20 | 6 | 4 |
The mean of the following distribution is 6. Find the value at P:
x | 2 | 4 | 6 | 10 | P + 5 |
f | 3 | 2 | 3 | 1 | 2 |