Advertisements
Advertisements
प्रश्न
The correct equation for the degree of an associating solute, ‘n’ molecules of which undergoes association in solution, is
विकल्प
α = `("n"("i" - 1))/("n - 1")`
α2 = `("n"(1 - "i"))/("n - 1")`
α = `("n"("i" - 1))/("1 - n")`
α = `("n"(1 - "i"))/("n"("1 - i"))`
MCQ
उत्तर
α = `("n"("i" - 1))/("1 - n")`
shaalaa.com
Solubility of the Solutes
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Normality of 1.25M sulphuric acid is ______.
Which is the molality of a 10% w/w aqueous sodium hydroxide solution?
Equimolal aqueous solutions of NaCl and KCl are prepared, If the freezing point of NaCl is -2°C, the freezing point of KCl solution is expected to be ______.
Explain the effect of pressure on solubility.
How many moles of solute particles are present in one liter of 10-4 M potassium sulphate?
