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The diagonal of a rectangle is 60 m more than its shorter side and the larger side is 30 m more than the shorter side. Find the sides of the rectangle. - Mathematics

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प्रश्न

The diagonal of a rectangle is 60 m more than its shorter side and the larger side is 30 m more than the shorter side. Find the sides of the rectangle.

योग

उत्तर


Let the shorter side be x m.

Length of the other side = (x + 30) m

Length of hypotenuse = (x + 60) m

Using Pythagoras theorem,

(x + 60)2 = x2 + (x + 30)2

x2 + 3600 + 120x = x2 + x2 + 900 + 60x

x2 – 60x – 2700 = 0

x2 – 90x + 30x – 2700 = 0

x(x – 90) + 30(x – 90) = 0

(x – 90)(x + 30) = 0

x = 90, –30

But, x cannot be negative.

So, x = 90.

Thus, the sides of the rectangle are 90 m and (90 + 30) m = 120 m.

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सेलिना Mathematics [English] Class 10 ICSE
अध्याय 6 Solving (simple) Problems (Based on Quadratic Equations)
Exercise 6 (B) | Q 5 | पृष्ठ ७१

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