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The diameter of the moon is approximately one-fourth of the diameter of the earth. Find the ratio of their surface area. - Mathematics

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प्रश्न

The diameter of the moon is approximately one-fourth of the diameter of the earth. Find the ratio of their surface area.

योग

उत्तर

Let the diameter of earth be d. Therefore, the diameter of the moon will be `d/4`.

Radius of earth = `d/2`

Radius of moon = `1/2xxd/4 = d/8`

Surface area of moon = `4pi(d/8)^2`

Surface area of earth = `4pi(d/2)^2`

Required ratio = `(4pi(d/8)^2)/(4pi(d/2)^2)=4/64=1/16`

Therefore, the ratio between their surface areas will be 1 : 16.

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अध्याय 13: Surface Area and Volumes - Exercise 13.4 [पृष्ठ २२५]

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एनसीईआरटी Mathematics [English] Class 9
अध्याय 13 Surface Area and Volumes
Exercise 13.4 | Q 7 | पृष्ठ २२५

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