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The diameter of the moon is approximately one-fourth of the diameter of the earth. Find the ratio of their surface area. - Mathematics

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Question

The diameter of the moon is approximately one-fourth of the diameter of the earth. Find the ratio of their surface area.

Sum

Solution

Let the diameter of earth be d. Therefore, the diameter of the moon will be `d/4`.

Radius of earth = `d/2`

Radius of moon = `1/2xxd/4 = d/8`

Surface area of moon = `4pi(d/8)^2`

Surface area of earth = `4pi(d/2)^2`

Required ratio = `(4pi(d/8)^2)/(4pi(d/2)^2)=4/64=1/16`

Therefore, the ratio between their surface areas will be 1 : 16.

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Chapter 13: Surface Area and Volumes - Exercise 13.4 [Page 225]

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NCERT Mathematics [English] Class 9
Chapter 13 Surface Area and Volumes
Exercise 13.4 | Q 7 | Page 225

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