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प्रश्न
The electronic configuration of \[\ce{Cu(II)}\] is 3d9 whereas that of \[\ce{Cu(I)}\] is 3d10. Which of the following is correct?
विकल्प
\[\ce{Cu(II)}\] is more stable
\[\ce{Cu(II)}\] is less stable
\[\ce{Cu(I)}\] and \[\ce{Cu(II)}\] are equally stable
Stability of \[\ce{Cu(I)}\] and \[\ce{Cu(II)}\] depends on nature of copper salts
उत्तर
\[\ce{Cu(II)}\] is more stable
Explanation:
\[\ce{Cu(II)}\] is more stable due to greater effective nuclear charge of \[\ce{Cu(II)}\].
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संबंधित प्रश्न
Explain giving reason:
Transition metals and many of their compounds show paramagnetic behaviour.
Write down the electronic configuration of Cr3+.
Write down the electronic configuration of Pm3+.
Write down the electronic configuration of Co2+.
Write down the electronic configuration of Mn2+.
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Electronic configuration of Cu3+ is ____________.
Explain the observation, at the end of each period, there is a slight increase in the atomic radius of d-block elements.
Name the element of 3d series which exhibits the largest number of oxidation states. Give reason.
Give reason for the following statements:
Scandium (Z = 21) is a transition element but Zn (Z = 30) is not.
