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Question
The electronic configuration of \[\ce{Cu(II)}\] is 3d9 whereas that of \[\ce{Cu(I)}\] is 3d10. Which of the following is correct?
Options
\[\ce{Cu(II)}\] is more stable
\[\ce{Cu(II)}\] is less stable
\[\ce{Cu(I)}\] and \[\ce{Cu(II)}\] are equally stable
Stability of \[\ce{Cu(I)}\] and \[\ce{Cu(II)}\] depends on nature of copper salts
Solution
\[\ce{Cu(II)}\] is more stable
Explanation:
\[\ce{Cu(II)}\] is more stable due to greater effective nuclear charge of \[\ce{Cu(II)}\].
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