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प्रश्न
The equation of a stationary wave is given by 2 sin `((pi"x")/15) "cos" (48 pi"t").`The distance between a node and its next antinode is ____________.
विकल्प
22.5 units
7.5 units
30 units
1.5 units
MCQ
रिक्त स्थान भरें
उत्तर
The equation of a stationary wave is given by 2 sin `((pi"x")/15) "cos" (48 pi"t").`The distance between a node and its next antinode is 7.5 units.
Explanation:
`"Y" = 2 "sin" ((pi "x")/15) "cos" (48 pi"t")`
`therefore "k" = pi/15`
`therefore (2pi)/ lambda = pi/15 Rightarrow lambda = 30 "units"`
Distance between a node and its next antinode is
`lambda/4 = 30/4 = 7.5 "units"`
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Stationary Waves
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