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The equation of a stationary wave is given by 2 sin xcost(πx15)cos(48πt).The distance between a node and its next antinode is ____________. -

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Question

The equation of a stationary wave is given by 2 sin `((pi"x")/15) "cos" (48 pi"t").`The distance between a node and its next antinode is ____________.

Options

  • 22.5 units

  • 7.5 units

  • 30 units

  • 1.5 units

MCQ
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Solution

The equation of a stationary wave is given by 2 sin `((pi"x")/15) "cos" (48 pi"t").`The distance between a node and its next antinode is 7.5 units.

Explanation:

`"Y" = 2  "sin" ((pi "x")/15) "cos" (48 pi"t")`

`therefore "k" = pi/15`

`therefore (2pi)/ lambda = pi/15 Rightarrow lambda = 30  "units"`

Distance between a node and its next antinode is

`lambda/4 = 30/4 = 7.5  "units"`

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Stationary Waves
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