Question

The excess pressure inside a liquid drop is 500 Nm^-2. If the radius of the drop is 2 mm, the surface tension of the liquid is x × 10^-3 Nm^-1. The value of x is ______.

विकल्प

• 200

• 100

• 300

• 500

Answer 1

The excess pressure inside a liquid drop is 500 Nm^-2. If the radius of the drop is 2 mm, the surface tension of the liquid is x × 10^-3 Nm^-1. The value of x is 500.

Explanation:

`P = P_0 + (2T)/R ⇒ P - P_0 = (2T)/R`

`500 = (2 xx T)/(2 xx 10^-3)`

T = 500 × 10^-3

So, x = 500