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प्रश्न
The focal length of a concave lens is 20 cm. At what distance from the lens should a 5 cm tall object be placed so that its image is formed at a distance of 15 cm from the lens? Also calculate the size of the image formed.
उत्तर
Focal length of concave lens, f = −20 cm
Distance of the image from the lens, v = -15 cm
Using the lens formula, we get:
`1/f=1/v - 1/u`
`1/-20= 1/-15 - 1/u`
`1/u=1/-15-1/-20`
`1/u=(-4+3)/60 = (-1)/60`
`u=-60 "cm"`
To find the size of the image formed (h′), use the magnification formula, where magnification (m) = `h^'/h = v/u` and h is the height of the object.
h=5 cm, and we have v = -15 cm and u = -60 cm
`m = (-15)/-60=1/4`
`h^' = mxxh = 1/4xx5 =1.25`
Hence, the size of the image is 1.25 cm.
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संबंधित प्रश्न
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(A) 20 cm on the other side of the lens and is of the same size, real and erect.
(B) 40 cm on the other side of the lens and is magnified, real and inverted.
(C) 20 cm on the other side of the lens and is of the same size, real and inverted.
(D) 20 cm on the other side of the lens and is of the same size, virtual and erect.
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(a) Write the type of mirror.
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(c) What is the focal length of the mirror?
(d) Draw the ray diagram to show the image formation in this case.
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S. No. |
Object distance (cm) |
Image distance (cm) |
1 | 60 | 15 |
2 | 48 | 16 |
3 | 36 | 21 |
4 | 24 | 24 |
5 | 18 | 36 |
6 | 16 | 48 |
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(A) 2
(B) 3
(C) 5
(D) 6
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