Question

The general solution of 4sin² x = 1 is ______.

विकल्प

• `"n"pi+pi/6`

• `"n"pi-pi/6`

• `"n"pi+-pi/6`

• `2"n"pi+-pi/6`

Answer 1

The general solution of 4sin² x = 1 is `underline("n"pi+-pi/6)`.

Explanation:

4 sin² x = 1

`=>sin^2x=1/4`

`=>sin^2x=(sin  pi/6)^2=sin^2(pi/6)`

`=>theta="n"pi+-pi/6,  "n"inZ`   ...[∵ sin²θ = sin²α ⇒ θ = nπ ± α]