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The general solution of 4sin2 x = 1 is ______. -

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Question

The general solution of 4sin2 x = 1 is ______.

Options

  • `"n"pi+pi/6`

  • `"n"pi-pi/6`

  • `"n"pi+-pi/6`

  • `2"n"pi+-pi/6`

MCQ
Fill in the Blanks

Solution

The general solution of 4sin2 x = 1 is `underline("n"pi+-pi/6)`.

Explanation:

4 sin2 x = 1

`=>sin^2x=1/4`

`=>sin^2x=(sin  pi/6)^2=sin^2(pi/6)`

`=>theta="n"pi+-pi/6,  "n"inZ`   ...[∵ sin2θ = sin2α ⇒ θ = nπ ± α]

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Trigonometric Equations and Their Solutions
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