Question

The intercepts of the plane 3x - 4y + 6z = 48 on the co-ordinate axes are ______

विकल्प

• (8, -12, 8)

• (16, 12, -8)

• (16, -12, 8)

• (-16, 20, -8)

Answer 1

The intercepts of the plane 3x - 4y + 6z = 48 on the co-ordinate axes are (16, -12, 8).

Explanation:

3x - 4y + 6z = 48 

⇒ `(3x)/48 - (4y)/48 + (6z)/48 = 1 ⇒ x/16 + y/(-12) + z/8 = 1`

∴ the intercepts are (16, -12, 8).