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Question
The intercepts of the plane 3x - 4y + 6z = 48 on the co-ordinate axes are ______
Options
(8, -12, 8)
(16, 12, -8)
(16, -12, 8)
(-16, 20, -8)
MCQ
Fill in the Blanks
Solution
The intercepts of the plane 3x - 4y + 6z = 48 on the co-ordinate axes are (16, -12, 8).
Explanation:
3x - 4y + 6z = 48
⇒ `(3x)/48 - (4y)/48 + (6z)/48 = 1 ⇒ x/16 + y/(-12) + z/8 = 1`
∴ the intercepts are (16, -12, 8).
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