हिंदी

The joint equation of the angle bisectors of the angles between the lines 4x2 – 16xy + 7y2 = 0 is ______. -

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प्रश्न

The joint equation of the angle bisectors of the angles between the lines 4x2 – 16xy + 7y2 = 0 is ______.

विकल्प

  • 8x2 – 3xy + 8y2 = 0

  • 8x2 + 3xy + 8y2 = 0

  • 8x2 + 3xy – 8y2 = 0

  • 8x2 – 3xy – 8y2 = 0

MCQ
रिक्त स्थान भरें

उत्तर

The joint equation of the angle bisectors of the angles between the lines 4x2 – 16xy + 7y2 = 0 is 8x2 – 3xy – 8y2 = 0.

Explanation:

4x2 – 16xy + 7y2 = 0

Here a = 4,

b = 7,

h = –8

Equation of angle bisector is:

`(x^2 - y^2)/(a - b) = (xy)/h`

∴ `(x^2 - y^2)/-3 = (xy)/-8`

∴ 8x2 – 8y2 = 3xy

∴ 8x2 – 3xy – 8y2 = 0

shaalaa.com
Angle between lines represented by ax2 + 2hxy + by2 = 0
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