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प्रश्न
The joint equation of the angle bisectors of the angles between the lines 4x2 – 16xy + 7y2 = 0 is ______.
पर्याय
8x2 – 3xy + 8y2 = 0
8x2 + 3xy + 8y2 = 0
8x2 + 3xy – 8y2 = 0
8x2 – 3xy – 8y2 = 0
MCQ
रिकाम्या जागा भरा
उत्तर
The joint equation of the angle bisectors of the angles between the lines 4x2 – 16xy + 7y2 = 0 is 8x2 – 3xy – 8y2 = 0.
Explanation:
4x2 – 16xy + 7y2 = 0
Here a = 4,
b = 7,
h = –8
Equation of angle bisector is:
`(x^2 - y^2)/(a - b) = (xy)/h`
∴ `(x^2 - y^2)/-3 = (xy)/-8`
∴ 8x2 – 8y2 = 3xy
∴ 8x2 – 3xy – 8y2 = 0
shaalaa.com
Angle between lines represented by ax2 + 2hxy + by2 = 0
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