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प्रश्न
The least count of a vernier callipers is 0.0025 cm and it has an error of + 0.0125 cm. While measuring the length of a cylinder, the reading on the main scale is 7.55 cm, and the 12th vernier scale division coincides with the main scale. Calculate the corrected length.
उत्तर
Least count (L.C.) = 0.0025 cm
Error = +0.0125 cm
Correction = – (Error) = – (+0.0125) = – 0.0125 cm
Main scale reading = 7.55 cm
Vernier scale division (V.S.D.) coinciding with main scale = 12th
Length recorded = Main scale reading + L.C. × V.S.D.
= 7.55 + 0.0025 × 12
= 7.55 + 0.0300
= 7.58 cm
Correct length = Length recorded + Correction
= 7.58 + (−0.0125)
= 7.58 – 0.0125
= 7.5675 cm
= 7.567 cm
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संबंधित प्रश्न
A vernier callipers has its main scale graduated in mm and 10 divisions on its vernier scale are equal in length to 9 mm. When the two jaws are in contact, the zero of the vernier scale is ahead of the zero of the main scale and the 3rd division of the vernier
scale coincides with a main scale division.
Find : (i) The least count and
(ii) The zero error of the vernier callipers.
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