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The mean and standard deviation of a binomial variate X are respectively 6 and 2. Find P(X = 3) - Mathematics

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प्रश्न

The mean and standard deviation of a binomial variate X are respectively 6 and 2. Find P(X = 3)

योग

उत्तर

X ~ B(n, p)

Given, Mean = 6

Standard deviation = 2

np = 6, `sqrt("npq")` = 2

npq = 4

`"npq"/"np"= 4/6`

q = `2/3`

p = 1 – q = `1/3`

npq = 4

`n" xx 1/3 xx 2/3` = 4

n = 18

P(X = 3) = `""^18"C"_3 (1/3)^3 (2/3)^15`

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Theoretical Distributions: Some Special Discrete Distributions
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 11: Probability Distributions - Exercise 11.5 [पृष्ठ २१८]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 12 TN Board
अध्याय 11 Probability Distributions
Exercise 11.5 | Q 7. (ii) | पृष्ठ २१८

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