Question

The molarity of the solution prepared by dissolving 6.3 g of oxalic acid (H₂C₂O₄ · 2 H₂O) in 250 mL of water in mol L^-1 is x × 10^-2. The value of x is ______. (Nearest integer)

[Atomic mass: H : 1.0, C : 12.0, O : 16.0]

विकल्प

• 30

• 20

• 25

• 15

Answer 1

The molarity of the solution prepared by dissolving 6.3 g of oxalic acid (H₂C₂O₄ · 2 H₂O) in 250 mL of water in mol L^-1 is x × 10^-2. The value of x is 20.

Explanation:

\[\ce{[H2C2O4 * 2H2O]}\] = `("weight"//"M.W.")/("V"("L"))`

`=> x xx 10^-2 = (6.3//126)/(250//1000)`

x = 20