मराठी

The molarity of the solution prepared by dissolving 6.3 g of oxalic acid (H2C2O4 · 2 H2O) in 250 mL of water in mol L-1 is x × 10-2. The value of x is ______. (Nearest integer) -

Advertisements
Advertisements

प्रश्न

The molarity of the solution prepared by dissolving 6.3 g of oxalic acid (H2C2O4 · 2 H2O) in 250 mL of water in mol L-1 is x × 10-2. The value of x is ______. (Nearest integer)

[Atomic mass: H : 1.0, C : 12.0, O : 16.0]

पर्याय

  • 30

  • 20

  • 25

  • 15

MCQ
रिकाम्या जागा भरा

उत्तर

The molarity of the solution prepared by dissolving 6.3 g of oxalic acid (H2C2O4 · 2 H2O) in 250 mL of water in mol L-1 is x × 10-2. The value of x is 20.

Explanation:

\[\ce{[H2C2O4 * 2H2O]}\] = `("weight"//"M.W.")/("V"("L"))`

`=> x xx 10^-2 = (6.3//126)/(250//1000)`

x = 20

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×