Question

The order and degree of the differential equation `("d"^2"y")/"dx"^2 + (("d"^3"y")/"dx"^3) + x^(1/5) = 0` are respectively.

विकल्प

• 2, 3

• 3, 1

• 2, 5

• 3, 2

Answer 1

3, 1

Explanation:

`("d"^2"y")/"dx"^2 + (("d"^3"y")/"dx"^3) + x^(1/5) = 0`

`=> (("d"^"y")/"dx"^2 + x^(1/5))^3 = [- (("d"^3"y")/"dx"^3)]^3`

`=> (("d"^2"y")/"dx"^2 + x^(1/5)) = ("d"^3"y")/"dx"^3`

Here, the highest order derivative is `("d"^3"y")/"dx"^3` with power 1.

∴ order = 3 and degree = 1