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The order and degree of the differential equation dydxdydxd2ydx2+(d3ydx3)+x15=0 are respectively. -

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Question

The order and degree of the differential equation `("d"^2"y")/"dx"^2 + (("d"^3"y")/"dx"^3) + x^(1/5) = 0` are respectively.

Options

  • 2, 3

  • 3, 1

  • 2, 5

  • 3, 2

MCQ

Solution

3, 1

Explanation:

`("d"^2"y")/"dx"^2 + (("d"^3"y")/"dx"^3) + x^(1/5) = 0`

`=> (("d"^"y")/"dx"^2 + x^(1/5))^3 = [- (("d"^3"y")/"dx"^3)]^3`

`=> (("d"^2"y")/"dx"^2 + x^(1/5)) = ("d"^3"y")/"dx"^3`

Here, the highest order derivative is `("d"^3"y")/"dx"^3` with power 1.

∴ order = 3 and degree = 1

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