Question

The oxidation number of Cr in \[\ce{Cr(OH)^-_4}\] ion is ______.

विकल्प

• - 4

• - 1

• + 3

• + 4

Answer 1

The oxidation number of Cr in \[\ce{Cr(OH)^-_4}\] ion is + 3.

Explanation:

\[\ce{Cr(OH)^-_4}\]

Oxidation state of Cr = x

x + 4(-1) = - 1

x - 4 = - 1

∴ x = + 3