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Question
The oxidation number of Cr in \[\ce{Cr(OH)^-_4}\] ion is ______.
Options
- 4
- 1
+ 3
+ 4
MCQ
Fill in the Blanks
Solution
The oxidation number of Cr in \[\ce{Cr(OH)^-_4}\] ion is + 3.
Explanation:
\[\ce{Cr(OH)^-_4}\]
Oxidation state of Cr = x
x + 4(-1) = - 1
x - 4 = - 1
∴ x = + 3
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Oxidation Number
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