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सी.आई.एस.सी.ई.आईसीएसई ICSE Class 7

The Perimeter of a Rectangle is 28x3+ 16x2 + 8x + 4. One of Its Sides is 8x2 + 4x. Find the Other Side - Mathematics

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प्रश्न

The perimeter of a rectangle is 28x3+ 16x2 + 8x + 4. One of its sides is 8x2 + 4x. Find the other side 

योग

उत्तर

Perimeter of a rectangle (2l + 2b)

= 28x3 + 16x2 + 8x + 4 

Let one side (l) = 8x2 + 4x

∴ 2l = 2 (8x2 + 4x) = 16x2 + 8x

∴ 2b = (28x3 + 16x2 + 8x + 4) - (16x2 + 8x)

= 28x3 + 16x2 + 8x + 4 - 16x2 - 8x 

= 28x3 + 4

∴ Other side (b) = `(28"x"^3 + 4)/2 = 14"x"^3 + 2`

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 11: Fundamental Concepts (Including Fundamental Operations) - Exercise 11 (B)

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सेलिना Concise Mathematics [English] Class 7 ICSE
अध्याय 11 Fundamental Concepts (Including Fundamental Operations)
Exercise 11 (B) | Q 18
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