Advertisements
Advertisements
प्रश्न
The perimeter of a rectangle is 28x3+ 16x2 + 8x + 4. One of its sides is 8x2 + 4x. Find the other side
उत्तर
Perimeter of a rectangle (2l + 2b)
= 28x3 + 16x2 + 8x + 4
Let one side (l) = 8x2 + 4x
∴ 2l = 2 (8x2 + 4x) = 16x2 + 8x
∴ 2b = (28x3 + 16x2 + 8x + 4) - (16x2 + 8x)
= 28x3 + 16x2 + 8x + 4 - 16x2 - 8x
= 28x3 + 4
∴ Other side (b) = `(28"x"^3 + 4)/2 = 14"x"^3 + 2`
APPEARS IN
संबंधित प्रश्न
Find the excess of 4m2 + 4n2 + 4p2 over m2+ 3n2 – 5p2
If x = 4a2 + b2 - 6ab; y = 3b2 - 2a2 + 8ab and z = 6a2 + 8b2 - 6ab find: x - y - z
If m = 9x2 - 4xy + 5y2 and n = - 3x2 + 2xy - y2 find: m + 2n
Simplify: 2x - y + 5 - (x - y)
Multiply: 5, 3a and 2ab2
Copy and complete the following multi-plication:
ax - b
× 2ax + 2b2
Simplify: `"a"/10+"2a"/5`
Simplify: `"4a"/7 + "2a"/3 - "a"/7`
Simplify: `"x" + "x"/2 + "x"/3`
Simplify: `"k + 1"/2 + "2k - 1"/3 - "k + 3"/4`
