Question

The pH of a 0.02 M NH₄Cl solution will be ______.

[Given: K_b(NH₄OH] = 10⁻⁵ and log 2 = 0.301)

विकल्प

• 2.65

• 4.35

• 4.65

• 5.35

Answer 1

The pH of a 0.02 M NH₄Cl solution will be 5.35.

Explanation:

pH = `7 - 1/2"pK"_"b" - 1/2 log "C"`

= `7 - 5/2 - 1/2 (log 2 xx 10^-2)`

= 5.35