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Question
The pH of a 0.02 M NH4Cl solution will be ______.
[Given: Kb(NH4OH] = 10−5 and log 2 = 0.301)
Options
2.65
4.35
4.65
5.35
MCQ
Fill in the Blanks
Solution
The pH of a 0.02 M NH4Cl solution will be 5.35.
Explanation:
pH = `7 - 1/2"pK"_"b" - 1/2 log "C"`
= `7 - 5/2 - 1/2 (log 2 xx 10^-2)`
= 5.35
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Ionization of Acids and Bases - Hydrolysis of Salts and the Ph of Their Solutions
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