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The population of a town increases at a rate proportional to the population at that time. If the population increases from 40 thousands to 60 thousands in 40 years ? - Mathematics and Statistics

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प्रश्न

The population of a town increases at a rate proportional to the population at that time. If the population increases from 40 thousands to 60 thousands in 40 years, what will be the population in another 20 years?

(Given: `sqrt(3/2)= 1.2247)`

योग

उत्तर

Step 1: Use the Exponential Growth Model

P(t) = P0​ekt

where:

  • P = Population at time t
  • P0 = Initial population
  • k = Growth constant
  • t = Time in years

Step 2: Find k Using Given Data

We are given:

  • P0 = 40,000 
  • P(40) = 60,000
  • t = 40 years

60,000 = 40,000e40k

`(60,000)/(40,000) = e^(40k)`

1.5 = e40k

Taking the natural logarithm:

ln (1.5) = 40k

`k = ln(1.5)/40`

Using ln⁡ (1.5) = 0.4055

`k = 0.4055/40 = 0.01014`

Step 3: Find Population After 60 Years

Now, we need to find P(60)

P(60) = 40,000e60k

P(60) = 40,000e60×0.01014

P(60) = 40,000e0.6084

P(60) = 40,000 × 1.837

P(60) ≈ 73,480

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Application of Differential Equations
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 8: Differential Equation and Applications - Exercise 8.6 [पृष्ठ १७०]

APPEARS IN

बालभारती Mathematics and Statistics 1 (Commerce) [English] 12 Standard HSC Maharashtra State Board
अध्याय 8 Differential Equation and Applications
Exercise 8.6 | Q 2 | पृष्ठ १७०

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