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प्रश्न
The position of \[\ce{-Br}\] in the compound in \[\ce{CH3CH = CH(Br)(CH3)2}\] can be classified as ______.
विकल्प
Allyl
Aryl
Vinyl
Secondary
उत्तर
The position of \[\ce{-Br}\] in the compound in \[\ce{CH3CH = CH(Br)(CH3)2}\] can be classified as Allyl.
Explanation:
It is allylic compound in which Br is attached next to double bonded carbon.
APPEARS IN
संबंधित प्रश्न
Name the following halide according to the IUPAC system and classify it as an alkyl, allyl, benzoyl (primary, secondary, tertiary), vinyl or aryl halide:
CH3CH=C(Cl)CH2CH(CH3)2
Name the following halide according to the IUPAC system and classify it as an alkyl, allyl, benzoyl (primary, secondary, tertiary), vinyl or aryl halide:
p-ClC6H4CH2CH(CH3)2
Match the structures of compounds given in Column I with the classes of compounds given in Column II.
| Column I | Column II | |
| (i) | \[\begin{array}{cc} \ce{CH3 - CH - CH3}\\ |\phantom{..}\\ \ce{X}\phantom{..} \end{array}\] |
(a) Aryl halide |
| (ii) | \[\ce{CH2 = CH - CH2 - X}\] | (b) Alkyl halide |
| (iii) |  |
(c) Vinyl halide |
| (iv) | \[\ce{CH2 = CH - X}\] | (d) Allyl halide |
Classify the following compound as a primary, secondary and tertiary halide.
1-Bromobut-2-ene
Name the following halide according to the IUPAC system and classify them as alkyl, allyl, benzyl (primary, secondary, tertiary), vinyl, or aryl halide:
\[\ce{CH3CH2C(CH3)2CH2I}\]
Name the following halides according to IUPAC system and classify them as alkyl, allyl, benzyl (primary, secondary, tertiary), vinyl or aryl halides:
\[\ce{CH3C(C2H5)2CH2Br}\]
Give the IUPAC name of the compound.
\[\ce{CICH2 C ≡ CCH2 Br}\]
Name the following halide according to IUPAC system and classify as alkyl, allyl, benzyl (primary, secondary, tertiary), vinyl or aryl halide:
\[\ce{CH3C(Cl)(C2H5)CH2CH3}\]
Write the structure of the following organic halogen compound.
4-tert-Butyl-3-iodoheptane
Name the following halide according to IUPAC system and classify them as alkyl, allyl, benzyl (primary, secondary, tertiary), vinyl or aryl halides:
\[\ce{CH3C(C2H5)2CH2Br}\]
