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प्रश्न
The product of oxidation of I– with \[\ce{MnO^{-}4}\] in alkaline medium is:-
विकल्प
\[\ce{IO^{-}3}\]
\[\ce{I_2}\]
\[\ce{IO^{-}}\]
\[\ce{IO^{-}4}\]
MCQ
उत्तर
\[\ce{IO^{-}3}\]
Explanation:
In an alkaline medium, KMnO4 is reduced to MNO4, and oxygen is produced.
\[\ce{2MnO^{-}4 + I^{-} + H2O -> 2MnO2 + IO^{-}3 + 2OH-}\]
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