Question

The product of oxidation of I^– with \[\ce{MnO^{-}4}\] in alkaline medium is:-

Options

• \[\ce{IO^{-}3}\]

• \[\ce{I_2}\]

• \[\ce{IO^{-}}\]

• \[\ce{IO^{-}4}\]

Answer 1

\[\ce{IO^{-}3}\]

Explanation:

In an alkaline medium, KMnO₄ is reduced to MNO₄, and oxygen is produced.

\[\ce{2MnO^{-}4 + I^{-} + H2O -> 2MnO2 + IO^{-}3 + 2OH-}\]