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प्रश्न
The rate constants of a reaction at 200 K and 500 K are 0.02 s–1 and 0.20 s–1 respectively. Calculate the value of Ea (Given 2.303 R = 19.15 JK-1 mol-1).
संख्यात्मक
उत्तर
`log ("k"_2/"k"_1) = "Ea"/(2.303 " R") [1/"T"_1 - 1/"T"_2]`
`log 0.20/0.05 = "Ea"/(2.303 " R") [1/200 - 1/500]`
log 10 = `"Ea"/19.15 (300/(200 xx 600))`
Ea = `(19.15 xx 200 xx 500)/300`
Ea = 6383 J/mol
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