Question

The S.I unit of electric permittivity is

विकल्प

• Nm²C^–2

• Am^–1

• NC^–1

• C²N^–1m^–2

Answer 1

C²N^–1m^–2 

Explanation:

The S.I unit of electric permittivity is [C²N^–1m^–2]. Coulomb's law states that the force between two charges is

F = ${\displaystyle \frac{q_1{q}_2}{4\pi E_0{r}^2} ={\sum }_0=\frac{q_1{q}_2}{4\pi F{r}^2}}$

or ${\displaystyle {\sum }_0=\frac{C.C}{N\cdot m^2}}$