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Question
The S.I unit of electric permittivity is
Options
Nm2C–2
Am–1
NC–1
C2N–1m–2
MCQ
Solution
C2N–1m–2
Explanation:
The S.I unit of electric permittivity is [C2N–1m–2]. Coulomb's law states that the force between two charges is
F = `(q_1q_2)/(4piE_0r^2) = ∑_0 = (q_1q_2)/(4piFr^2)`
or `∑_0 = (C.C)/(N*m^2)`
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