Advertisements
Advertisements
प्रश्न
The side of a square field is 16 m. What will be increase in its area, if each of its sides is doubled?
उत्तर
Side of a square field (a) = 16 m
∴ Area of a square field = (a)2
= 16 × 16 m2 = 256 m2
Each of its side is doubled
∴ New side = (16 × 2)m = 32 m
∴ New area of the square field = (a)2
= 32 × 32 m2 = 1024 m2
APPEARS IN
संबंधित प्रश्न
A point D is taken on the side BC of a ΔABC such that BD = 2DC. Prove that ar(Δ ABD) =
2ar (ΔADC).
In the given figure, ABCD is a rectangle with sides AB = 10 cm and AD = 5 cm. Find the area of ΔEFG.
ABCD is a parallelogram. P is any point on CD. If ar (ΔDPA) = 15 cm2 and ar (ΔAPC) = 20 cm2, then ar (ΔAPB) =
Diagonal AC and BD of trapezium ABCD, in which AB || DC, intersect each other at O. The triangle which is equal in area of ΔAOD is
ABCD is a rectangle with O as any point in its interior. If ar (ΔAOD) = 3 cm2 and ar (ΔABOC) = 6 cm2, then area of rectangle ABCD is
Find the area of a rectangle whose length = 3.6 m breadth = 90 cm
Find the area of a square, whose side is: 4.1 cm.
By counting squares, estimate the area of the figure.
In the same way, find the area of piece B.
Find all the possible dimensions (in natural numbers) of a rectangle with a perimeter 36 cm and find their areas.