Advertisements
Advertisements
प्रश्न
The slope in the plot of ln[R] vs. time for a first order reaction is ______.
विकल्प
`(+k)/2.303`
– k
`(-k)/2.303`
+ k
उत्तर
The slope in the plot of ln[R] vs. time for a first order reaction is – k.
Explanation:
For the reaction, R `rightarrow` Products
The integrated first order rate equation is
ln [R] = – kt + ln [R0]
Comparing the above equation with a straight line equation y = mx + c
∴ y = ln [R], x = t, slope = – k and intercept = ln [R0]
Thus, the slope for first order reaction is – k.
APPEARS IN
संबंधित प्रश्न
The time required for 10% completion of a first order reaction at 298 K is equal to that required for its 25% completion at 308 K. If the value of A is 4 × 1010 s−1. Calculate k at 318 K and Ea.
Following data are obtained for reaction :
N2O5 → 2NO2 + 1/2O2
t/s | 0 | 300 | 600 |
[N2O5]/mol L–1 | 1.6 × 10-2 | 0.8 × 10–2 | 0.4 × 10–2 |
1) Show that it follows first order reaction.
2) Calculate the half-life.
(Given log 2 = 0.3010, log 4 = 0.6021)
A first order reaction takes 20 minutes for 25% decomposition. Calculate the time when 75% of the reaction will be completed.
(Given : log = 2 = 0·3010, log 3 = 0·4771, log 4 = 0·6021)
Straight line graph for first order reaction is obtained between ____________.
State a condition under which a bimolecular reaction is kinetically first order reaction.
The reaction X → product
Follow first order of kinetics. In 40 minutes the concentration of 'X' changes from 0.1 m to 0.025. M. The rate of reaction when concentration of X is 0.01 m is.
Observe the graph shown in figure and answer the following questions:
- What is the order of the reaction?
- What is the slope of the curve?
- Write the relationship between k and t1/2 (half life period).
How will you represent first order reactions graphically?
Define first-order reaction.
The rate constant for the reaction:
\[\ce{2N2O_{(s)} ->2N2O4_{(g)}}\] is 4.98 × 10-4 s-1.
The order of the reaction is ______.