Advertisements
Advertisements
प्रश्न
The sum of the interior angles of a polygon is 6.5 times the sum of its exterior angles. Find the number of sides of the polygon.
उत्तर
Sum of the interior angles of a polygon = (n - 2) x 180°
Sum of the exterior angles of a polygon = 360°
Given,
Sum of the interior angles of a polygon
= 6.5...(Sum of the exterior angles of a polygon)
∴ (n - 2) x 180°
= 6.5 x 360°
⇒ n - 2 = 13
⇒ n = 15
∴ The polygon has 15 sides.
APPEARS IN
संबंधित प्रश्न
The angles of a pentagon are in the ratio 4: 8: 6: 4: 5.
Find each angle of the pentagon.
One angle of a six-sided polygon is 140o and the other angles are equal.
Find the measure of each equal angle.
Find the measure of each interior angle of a regular polygon of: 6 sides
Find each exterior angle of a regular polygon of: 18 sides
The angles of a pentagon are 100°, 96°, 74°, 2x° and 3x°. Find the measures of the two angles 2x° and 3x°.
Is it possible to have a polygon whose each interior angle is 124°?
Is it possible to have a polygon whose each interior angle is 105°?
A heptagon has three angles equal to 120°, and the other four angles are equal. Find all the angles.
If the difference between an exterior angle of a regular polygon of 'n' sides and an exterior angle of another regular polygon of '(n + 1)' sides is equal to 4°; find the value of 'n'.
Find the value of each angle of an octagon if two of its angles are 148° and 152° and the remaining angles are all equal.
