Advertisements
Advertisements
प्रश्न
The sum of the interior angles of a polygon is four times the sum of its exterior angles.
Find the number of sides in the polygon.
उत्तर
The sum of the interior angle=4 times the sum of the exterior angles.
Therefore the sum of the interior angles = 4 × 360° =1440°.
Now we have
( 2n - 4 ) x 90° = 1440°
2n - 4 = 16
2n = 20
n = 10
Thus the number of sides in the polygon is 10.
APPEARS IN
संबंधित प्रश्न
In a pentagon ABCDE, AB is parallel to DC and ∠A: ∠E : ∠D = 3: 4: 5. Find angle E.
In a parallelogram ABCD, AB = 20 cm and AD = 12 cm. The bisector of angle A meets DC at E and BC produced at F.
Find the length of CF.
Find the sum of the interior angles of a polygon of: 9 sides
Find the measure of each interior angle of a regular polygon of: 10 sides
Find the number of sides in a regular polygon, when each interior angle is: 120°
Find the number of sides in a regular polygon, when each exterior angle is: 72°
Is it possible to have a polygon whose sum of interior angles is 780°?
Is it possible to have a polygon whose each interior angle is 124°?
If the difference between an exterior angle of a regular polygon of 'n' sides and an exterior angle of another regular polygon of '(n + 1)' sides is equal to 4°; find the value of 'n'.
The exterior angle of a regular polygon is one-third of its interior angle. Find the number of sides of the polygon.
