Advertisements
Advertisements
प्रश्न
The sum of two numbers is 80. The larger number exceeds four times the smaller one by 5. Find the numbers.
उत्तर
Let the larger number be x and the smaller number be y.
Then as per the question
x + y = 80 …….(i)
x = 4y + 5
x – 4y = 5 …….(ii)
Subtracting (ii) from (i), we get
5y = 75 ⇒ y = 15
Now, putting y = 15 in (i), we have
x + 15 = 80 ⇒ x = 65
Hence, the numbers are 65 and 15.
APPEARS IN
संबंधित प्रश्न
Find the value of k for which each of the following systems of equations has infinitely many solutions :
2x + 3y − 5 = 0
6x + ky − 15 = 0
For what value of , the following system of equations will be inconsistent?
4x + 6y - 11 = 0
2x + ky - 7 = 0
Solve for x and y:
x – y = 3, `x/3 + y/2` = 6
Solve for x and y:
2x - `(3y)/4 = 3 ,5x = 2y + 7`
Solve for x and y:
7(y + 3) – 2(x + 2) = 14, 4(y – 2) + 3(x – 3) = 2
Solve for x and y:
`x/a + y/b = a + b, x/(a^2)+ y/(b^2) = 2`
Find the value of k for which the system of equations has a unique solution:
4x + ky + 8=0,
x + y + 1 = 0.
Find two numbers such that the sum of twice the first and thrice the second is 92, and four times the first exceeds seven times the second by 2.
A two-digit number is such that the product of its digits is 18. When 63 is subtracted from the number, the digits interchange their places. Find the number.
The present age of a woman is 3 years more than three times the age of her daughter. Three years hence, the woman’s age will be 10 years more than twice the age of her daughter. Find their present ages.
